(Answered) It seems like in order to generate a c9h10nbspproduct after

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It seems like in order to generate a C₉H₁₀ product after the tert-butanol elimination the Bromine that's added initially couldn't be on the any of the aromatic ring carbons, which inclines me to belive that answer A is correct. However, I have no idea why any of these answers wouldn't have multiple possible bromination locations, so I don't have any idea which one satisfies the criterium that it would only generate one C₉H₁₁Br intermediate. If someone can indicate the correct answer and also explain why it would generate only one the C₉H₁₁Br product and how it undergoes the second reaction to generate C₉H₁₀that'd be great!

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