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It is found that 4.68e-06 g of Nd2(CO3)3 dissolves per 100 mL of aqueous solution at 25 oC. Calculate the solubility-product constant for Nd2(CO3)3.
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For each of the following reactions identify the oxidizing agent and the reducing agent. 2Na(aq)+2H2O(l)→2NaOH(aq)+H2(g) C(s)+O2(g)→CO2(g) 2MnO-4(aq)+5SO2(g)+2H2O(l)→2Mn2+(aq)+5SO2-4(aq)+4H+(aq)
A student weighed out 1.74 grams of sodium hydroxide pellets and added them to 48.0 grams of water in a calorimeter. Extrapolating back to the time of mixing yielded a temperature change at the time of mixing equal to 9. ...
A watch glass and Filter paper weighing 41.060g was used to collect the CuSCN precipitate in this experiment. After drying, the precipitate, watch glass, and filter paper weighed 42.525g. If the sample alloy used for the ...
A mixture containing 3.3 moles of NO and 0.76 mole ofCO 2 was allowed to react in a flask at a certaintemperature according to the equation. NO (g) + CO 2 (g) ↔ NO2 (g) + CO (g) At equilibrium 0.21 mole of CO 2 was pr ...
What is the calculation of K c for the following reaction if an initial reaction mixture of 0.600 mole of CO and 1.80 mole of H 2 in a 6.00 liter container forms an equilibrium mixture containing 0.226 mole of H 2 O an ...
The reaction of solid dimethylhydrazine ((CH3)2N2H2) and liquefied dinitrogen tetroxide (N2O4) has been investigated as a rocket fuel; the reaction produces gaseous carbon dioxide (CO2) nitrogen (N2) and water vapor (H2O ...
Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show the formal charges of all atoms in the correct structure.
Calculate the volume of 6.0M NaOH solution that you would need to prepare 500mL of a .15M NaOH solution. (formula weight of NaOH = 40.00g/m)
If liquid is at or above it's flash point, the flame spread rate is fast, and the entire pool is engulfed within seconds. In such a case, the liquid is already evaporating sufficiently to reach the lower flammability lim ...
A chemistry lab experiment requires 67.4 grams of silvernitrate. How many grams of a 15.5% by mass solution of silvernitrate should be used?
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