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In the titration, Hbr+KOH>H2O+KBr, if 48.5mL of 1.5M HBr reached the end point of 50.0mL of the KOH, calculate the molarity of the KOH. 

Given the reaction Pb(NO3)2+2KI>PbI2+2KNO3, if 450mL of .50M Pb(NO3)2 is added to 350mL of the KI, what molarity would the KI have to be to completely react with all the Pb(NO3)2?

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