In the Tevatron accelerator/storage ring at the Fermi National Accelerator Laboratory, two beams of protons travel in opposite directions each with a total energy of 1 TeV and interact. Since these beams have momenta of equal magnitude but opposite direction, they interact in their center of momentum inertial frame. Hence s2 = 4TeV2. If one wished to achieve the same total energy in the center of momentum with a target proton at rest and a very high energy beam proton, what kinetic energy must this beam proton have?

1 TeV = 106 MeV