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In the formation of dibenzalacetone, do you expect the configuration of the double bonds in this compound to be E,Z, or a mixture of both? WHY?

This reaction is acetone + benzaldehyde treated with NaOH and then forming dibenzalacetone.

The molar ratio of the reactants in this reaction is 2:1. What would happen if the ratio was closer to 1:1?

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