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In an earlier problem we described the reaction of ammonia with oxygen to form nitrogen monoxide, NO.
4NH3 + 5O2 ? 4NO + 6H2O

How many grams of NO could be formed from a mixture 49.1 g of NH3 and 40.3 g of 02?

How many grams of NH3 would remain?

How many grams of O2 would remain?

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