In a classic carnival ride patrons stand against the wall, Ask an Expert

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In a classic carnival ride, patrons stand against the wall in a cylindrically shaped room. Once the room gets spinning fast enough, the floor drops from the bottom of the room! Friction between the walls of the room and the people on the ride make them the "stick" to the wall so they do not slide down. In one ride, the radius of the cylindrical room is R = 7.4 m and the room spins with a frequency of 19.7 revolutions per minute.

1) What is the speed of a person "stuck" to the wall?

2) What is the normal force of the wall on a rider of m = 47.0 kg?

3) What is the minimum coefficient of friction needed between the wall and the person?

4) If a new person with mass 94.0 kg rides the ride, what minimum coefficient of friction between the wall and the person would be needed?

5) To be safe, the engineers making the ride want to be sure the normal force does not exceed 2.2 times each persons weight - and therefore adjust the frequency of revolution accordingly. What is the minimum coefficient of friction now needed?

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Category:- Physics
Reference No.:- M91064055

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