(Answered) In a 2d box colliding with the left wall parallel to the

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In a 2D box colliding with the left wall, parallel to the x-axis. We assumed an elastic collision and found the change in momentum (dp)in the x-direction was dpx = 2mvx.

(a) If the particle was moving at an angle to the left wall, why does dpx = 2mvx anddpy = 0?

(b) After the particle collided with the left wall, it then collides with the top wall.What are dpx, and dpy after the collision with the top wall?

(c) Again, considering the momentum transferred to the left wall, if the particle ismoving in 3D why does dpx = 2mvx and dpy = dpz = 0?

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