If you start with 5.2x10^-2 m i2 at this temp, how much, Ask an Expert

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Molecular iodine, I2 (g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s-1. If you start with 5.2x10^-2 M I2 at this temp, how much will remain after 7.68s assuming that the iodine atoms do not recombine to form I2?

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