If i use a ph calculator to find the ph of 035m of citric, Ask an Expert

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If I use a pH calculator to find the ph of .035M of citric acid, I get a pH level of 2.32. However, when I try to find the pH by doing -log₁₀(.035*3), then I get a pH of 0.97. Why is this? If it helps, there are .00105 moles of NaOH and by the stoichiometric coefficient, .00035 moles of citric acid.

The equation in question is C₆H₈O₇+ 3(NaOH) -----> C₆H₈O₇Na₃ + 3(H₂O)

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Category:- Chemistry
Reference No.:- M91413815

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