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If 30.0mL of 0.250 M calcium nitrate is added to 1.25g of potassium phosphate, explain what is the mass (in grams) of the resulting calcium phosphate precipitate?
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The following sequence of reactions occurs in the commercial production of aqueous nitcric acid: 4NH3(g)+ 5O2(g) -> 4NO2 (g) + 6H2O(l) ΔH = -907 kJ 2NO(g) + O2(g) ? 2NO2(g) ΔH= -113 kJ 3NO2 + H2O(l) -> 2HNO3(aq) + NO(g) ...
Insoluble PbBr2(s) precipitates when solutions of Pb(NO3)2(aq) and NaBr(aq) are mixed. Pb(NO3)2(aq) + 2NaBr(aq) ---> PbBr2(s) + 2NaNO3(aq) ΔrH = ? To measure the enthalpy change, 350. mL of 0.50 M Pb(NO3)2(aq) and 350. ...
As a distributor, Testa Produce doesn't have direct contact with the public. How might the company go about alerting consumers to its "green" initiatives?
A gas is confined to a cylinder with a moveable piston (to allow the gas to expand or contract) under a pressure of 1 atmosphere. When the temperature of the gas is increased, 850 J of heat is added, and the gas expands, ...
2 H2S(g) + 3 O2(g) → 2 H2O(g) + 2 SO2(g) Using standard enthalpies of formation, calculate the standard enthalpy change for this reaction.
Assume that you dissolve 10.2 g of a mixture of NaOH and Ba(OH)2 in 227.0 mL of water and titrate with 1.47M hydrochloric acid. The titration is complete when 107.8 mL of the acid has been added. What is the mass (in gra ...
The density of air at STP is 1.29g/L. If your stoppered the250mL flask contains 242mL of water(also the volume of air it would contain), calculate the mass of air in the flask under STP.
When benzene (C6H6 ) reacts with bromine (Br2 ), bromobenzene (C6H5Br ) is obtained: C6H6+Br2→C6H5Br+HBr What is the theoretical yield of bromobenzene in this reaction when 28.0 g of benzene reacts with 60.7 g of bromine ...
When 3.56 g of an unknown hydrocarbon was dissolved in 125 g of benzene, the freezing pointof the solution was found to be 4.41oC. Analysis of thehydrocarbon showed that it contained 93.71% carbon (by mass) and6.29% hydr ...
Why do the instructions call for using a saturated solution of NaOH rather than one at lower concentration? Why can we ignored in the calculation of the concentration of NaOH?
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