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If 3.00 g of PbO2 was allowed to react with 2.00 g of Pb and 2.00 g of sulfuric acid, then 0.0116 mol of PbSO4 was obtained. What was the percent yield of PbSO4 (by weight) for this reaction?

PbO2+Pb+2H2SO4--> 2PbSO4+2H2O

PbO2 molecular weight= 239.2

Pb molecular weight= 207.2

H2SO4 molecular weight=98.1

PbSO4 molecular weight=303.3

H2O molecular weight=18.01

percent yield of PbSO4 (by weight) for this reaction?

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