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If 0.200 M NaI is slowly added to 20.00 mL of a solution that is 0.0500 M Pb2+, 0.0400 M Hg22+, 0.0600 M Ag2+, and 0.0800 M Tl+, in what order do the iodides precipitate? Ksp (PbI2) = 7.1 x 10-9, Ksp (AgI) = 8.31 x 10-17, Ksp (TlI) = 6.5 x 10-8, and Ksp(Hg2I2) = 4.5 x 10-29.

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Category:- Chemistry
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