According to the following equation, 20.00 g of NH3 (g) reacts in the presence of excess O2 (g) to produce NO (g) and H2O (l).
4NH3(g) + 5O2(g) ----> 4NO(g) + 6H2O(l) (delta)H= +1168 kJ
a. How much heat (kJ) is absorbed/ released?
b. What is the change in internal energy (kJ) if the reaction results in a volume change of - 2.78 L?