51.1mL of 0.415M KI is mixed with 59.2mL of 0.149M Pb(NO3)2 and diluted to 500mL
Equation:
2KI +Pb(NO3)2 ---> 2KNO3 + PbI2
How many moles of PbI2 are formed?
What is the concentration of KNO3?
What is the remaining concentration of the reactant that was in excess?