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How many milliliters of 0.105 M HCl are needed to titrate 50.0 mL of a solution that contains 1.25 g of NaOH per liter?
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The threshold wavelength for the photoelectric effect for silver is 262nm. What is the work function for silver and what is the maximum KE of an emitted electron if the incident light has a wavelength of 212nm?
When .514g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.8 degrees C to 29.4 degrees C. Find delta E(rxn) for the combustion of biphenylin kJ/mol. The heat capacity of the ...
For the equilibrium 2IBr( g )?I2( g )+Br2( g ) Kp =8.5×10-3 at 150 °C. Part A: If 2.7×10-2 atm of IBr is placed in a 2.0-L container, what is the partial pressure of IBr after equilibrium is reached? Express your answer ...
A 0.235g sample of a solid is 92.5% NaOH and 7.5% Ca(OH)2, by mass requires 45.6mL of a HCl solution for its titration. What is HCl molarity?
A solution of hydrochloric acid has a volume of 250. mL and a pH of 1.92. Exactly 250. mL on 0.0105 M NaOH is added. What is the pH of the resulting solution?
A gas is confined to a cylinder with a moveable piston (to allow the gas to expand or contract) under a pressure of 1 atmosphere. When the temperature of the gas is increased, 850 J of heat is added, and the gas expands, ...
2KMnO 4 (s) → K 2 MnO 4 (s) + MnO 2 (s) + O 2 (g) If 2.50 L of O 2 (g) is needed at 1.00 atm and 20°C, what mass of KMnO 4 (s) should be decomposed? Assume the decomposition of KMnO 4 (s) goes to completion.
An analysis of an oxide of nitrogen with a molecular weight of92.02 amu gave 69.57% oxygen and 30.43 % nitrogen. What is the empirical formula of the compound?
A 20.0 mL sample of 0.200 M HBr solution is titratedwith 0.200 M NaOH solution. Calculate the pH of the solution after the following volumes of base have been added. (19.8 mL)
A 43 kg person drinks 430 g of milk, which has a "caloric" value ofapproximately 3.0 kJ/g. If only 15% ofthe energy in milk is converted to mechanical work, how high (inmeters) can the person climb based on this energy i ...
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