In an earlier problem we described the reaction of ammonia with oxygen to form nitrogen monoxide, NO.
4NH3 + 5O2 â†' 4NO + 6H2O
1. How many grams of NO could be formed from a mixture of 44.7 g of NH3 and 42.7 g of O2?
2. How many grams of NH3 would remain?
3. How many grams of O2 would remain?