Given the following thermochemical equationsc2h2g 52 o2g, Ask an Expert

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Given the following thermochemical equations,

C2H2(g) + 5/2 O2(g) -----> 2CO2(g) + H2O(l) enthalpy = -1299.5 kJ

C(s) + O2(g) -----> CO2(g) enthalpy = -393.5 kJ

H2(g) + 1/2O2(g) -----> H2O(l) enthalpy = -285.8 kJ

calculate the enthalpy for the reaction below

2C (s) + H2(g) = C2H2 Delta H =

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Category:- Chemistry
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