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Given the following thermochemical equation: NO(g) + O3(g) ---> NO2(g) + O2(g) delta H= -198.9 KJ/mol O3(g) ----> 3/2 O2(g) delta H= -142.3 KJ/mol O2(g) ----> 2O(g) delta H= +495 KJ/mol determine the enthalpy change for the reaction: 2NO2(g) ----> 2NO(g)+O2(g) delta H

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