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Given the following data:
N2O4(g) --> 2NO2(g)delta H = 24.3 kJ
NO(g) + NO2(g) --> N2O3(g)delta H = -40.2 kJ
Calculate delta H for the reaction: 2N2O3(g) --> N2O4(g) + 2NO(g)
Answer is in kJ
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