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Given the following bond enthalpy values, calculate the enthalpy of formation for gas phase isopropanol, C3H7OH at 25 °C.

BE (C-C) = 346 kJ mol-1

BE (C-H) = 4.00 × 102 kJ mol-1

BE (C-O) = 352 kJ mol-1 BE (O-H) = 465 kJ mol-1

BE (O=O) = 498 kJ mol-1 BE (H-H) = 432 kJ mol-1

The enthalpy of formation of C(g) is 715.0 kJ mol-1.

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