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Given the following balanced chemical equation, how many mol of NaN3 can be formed if 2.50 mol of Na are allowed to react with 4.50 mol of N2? 2Na +3N2 --> 2NaN3
A. 2.50 mol NaN3
B. 3.00 mol NaN3
C. 4.50 mol NaN3
D. 7.00 mol NaN3
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