A. The activation energy of a certain reaction is 36.8 kJ/mol at 28 degrees celsius the rate constant is 0.0190s^-1 at what temperature in degrees celsius would this reaction go twice as fast?
B. Given that the initial rate constant is 0.0190s^-1 at an initial temperature of 28 degrees celsius what would the rate constant be at a temperature of 150 degrees celsius for the same reaction descrabed in part A?