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From the volume of NaHCO3 solution used and the initial mass of NaHCO3 used, determine the mass of NaHCO3 present in each trial. Calculate the moles of NaHCO3 present in each trial you conducted.
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Titrate the base trimethylamine (TMA) with 0.126 M HCl. (CH) 3 N(aq) + H 2 O(l) (CH 3 ) 3 NH+(aq) + OH-(aq) Kb = 6.45 x 10 -5 There are 0.00615 moles of TMA in 42.5 mL H 2 O before titration begins. What percent of TMA i ...
For the reaction 2CH4(g)?C2H2(g)+3H2(g) K = 0.170 at 1725 °C. What is K p for the reaction at this temperature? Express your answer numerically. For the reaction N2(g)+3H2(g)?2NH3(g) K p= 3.95×10 -3 at 325 °C . What i ...
Why do the instructions call for using a saturated solution of NaOH rather than one at lower concentration? Why can we ignored in the calculation of the concentration of NaOH?
A photon of wavelength 200 nm strikes the surface of a metal causing an electron to be ejected with kinetic energy of 4.3 x 10-19 J. What was the threshold frequency of the metal?
What is the mass percent of oxygen in Manganese (IV) phosphate? How many cubic feet (ft 3 ) are 5.14E+08 gallons (gal) of water? The density of water at ambient conditions is 1.000 g/mL
What is the volume of a solution with a concentration of 1.2 M that contains 12 g of NaOH?
Label each of the following phase changes as either exothermic or endothermic. i. H 2 O( s ) + heat H 2 O( l ) (1 point) ii. H 2 O( g ) H 2 O( l ) + heat (1 point)
Aqueous lithium sulfate was mixed with aqueous strontium chlorate, and a crystallized strontium sulfate product was formed. Consider the other product and its phase, and then write the balanced molecular equation for t ...
Calculate the volume in milliliters of a 0.616M barium chlorate solution that contains 475.mmol of barium chlorate (Ba(ClO3)2). Round your answer to 3 significant digits.
22.8 g of an unknown molecular solute is dissolved in 4.28 moles of 1,2-ethanediol (C2H6O2), causing the freezing point of 1,2-ethanediol to decrease by 1.08 °C. Calculate the molar mass of the solute. For 1,2-ethanediol ...
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