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For the reaction 4NH3(g)+ 5 O2(g)= 4NO(g)+ 6H2O(l) a.) Use the following standard enthalpies of formation to calculate the enthalpy change. NH3(g)= -46.11 kJ/mol O2(g)= 0 kJ/mol NO(g)= 90.25 kJ/mol H2O(l)= -285.83 kJ

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