For the isomerization of n-butane to isobutene we have g, Ask an Expert

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For the isomerization of n-butane to isobutene we have G= -RT LnK where R= 1.9872 and K= (isobutene)/(n-butane) The temperature dependent Gibbs free energy (in calories) for isobutene and nbutane are given by G= -31450 - 70.42 T and G= -29810- 74.10T respectively a) find K as a function of T b) find the max temperature for which K is greater than or equal to 1 c) does it seem preferable to carry out the reaction at a low temp?

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