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For each of the following pairs of compounds, explain the difference in melting point in terms of the intermolecular forces involved.

a) hexane (C6H14) m.p. = -96 0C vs. octadecane (C18H38) m.p. = 28 - 30 0C

b) toluene (Ph-CH3) m.p. = 5.5 0C vs. benzoic acid (Ph-CO2H) m.p. = 122.4 0C

c) benzoic acid (Ph-CO2H) m.p. = 122.4 0C vs. sodium benzoate (Ph-CO2Na) m.p. = 300 0C

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