Explain the rate law for the solvolysis of benzyl bromide, Ask an Expert

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Explain the rate law for the solvolysis of benzyl bromide in 50% ethanol/50% water at room temperature (24C) is given by: rate = 2.9 x 10-5 (benzyl bromide)(OH-) + (benzyl bromide)
Compute the percent of the reaction that takes place by each of the two nucleophilic substitution mechanisms (Sn1 and Sn2) when
a) OH- = 0.500 M
b) OH- = 0.0005 M
c) Comment on your results:

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