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Do a calculation to check the claim that to fully neutralize 17,000 tons of CaCO3 would require enough 0.0005 M H2SO4 to fill 8 millions swimming pools.

H2SO4 + CaCO3 --> CaSO4 + CO2 + H2O

volume of swimming pool = 1250 m squared.

molar mass of CaCO3 = 100.1 g/mol

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Category:- Chemistry
Reference No.:- M9684832

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