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Analysis of a volatile liquid shows that it contains 37.21 percent carbon, 7.81 percent hydrogen, and 54.96 percent chlorine by mass. At 249.0 °C and 4.9 atm, 712.0 mL of the vapor has a mass of 5.249 g. What is the molar mass of the compound?

PART TWO

For the compound above, determine the molecular formula. Enter your formula as plain text, with carbon first, then hydrogen, the chlorine. So if the formula were C10H21Cl, you would enter C10H21Cl.

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