Coulombs law for the magnitude of the force f between two, Ask an Expert

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Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

|F|= K(|QQ'|/d²),

Where K = (1/ 4 Πε₀), and ε₀= 8.854 x 10^-12 C²/(Nm²) is permittivity of free space.

Consider two point charges located on the x axis: one charge q₁ = -18.0 nC is located at x₁ = -1.670m; the second charge q₂ = 33.0 nC is at the origin (x = 0.0000).

What is the net force exerted by these two charges on a third charge q₃ = 49.5 nC placed between q₁ and q₂ at x₃ = -1.195m?

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