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Construct a delta H and delta S table, including the four possibilities associated with the two possible signs for each of delta H and delta S. Discuss the resulting sign of delta G and the spontaneity of the process.
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A chemist must prepare 725. mL of 275. mM aqueous copper(II) sulfate CuSO4 working solution. He'll do this by pouring out some 0.316 M aqueous copper(II) sulfate stock solution into a graduated cylinder and diluting it w ...
Determine if the reactants shown on the right would result in the formation of a precipitate. Choices can be used more than one time or not at all. Forms a precipitate Will not form a precipitate Na 2 SO 4 + Ba(NO 3 ) 2 ...
Suppose that you take .5000 gram of Na2CO3 and titrate it with .115M HCL solution. What is the equivalence point volume expected for the complete titration? (Formula weights Na2CO3 = 105.99g/mol and HCL = 36.46g/mol)
The heat fusion of pure silicon is 43.4 kJ/mol. How much energy would be needed to melt a 5.24 - g sample of silicon at its melting point of 1693 K?
A power plant converts the heat energy in coal to electricity with 35% efficiency. Transmission losses are 10%. A factory then uses that electricity to make hydrogen with 50% efficiency, which is used in a fuel cell to m ...
How many grams of H2SO4 must be dissolved into 0.709 L of solution to generate a concentration of 0.303 M?
Suppose that a student is determining the total base content of an antacid tablet by performing a back titration. He/she weighs out a .3012g portion of a tablet whose total weight is 1.5312g, dissolves this in exactly 40 ...
A 20.0 mL sample of 0.200 M HBr solution is titratedwith 0.200 M NaOH solution. Calculate the pH of the solution after the following volumes of base have been added. (19.8 mL)
For the equilibrium 2IBr( g )?I2( g )+Br2( g ) Kp =8.5×10-3 at 150 °C. Part A: If 2.7×10-2 atm of IBr is placed in a 2.0-L container, what is the partial pressure of IBr after equilibrium is reached? Express your answer ...
Why do the instructions call for using a saturated solution of NaOH rather than one at lower concentration? Why can we ignored in the calculation of the concentration of NaOH?
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