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Considering an unbalanced equation given as Ca3(PO4)2 + H2SO4 --> CaSO4 + H3PO4 for the reaction of calcium phosphate with sulfuric acid(Ca3(PO4)2 + H2SO4)  now determine the limiting reactant if 140 grams of Calcium phosphate combines with 3.63 mol of sulphuric acid and also explain how many moles of calcium  sulphate  can be obtained?

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