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Consider the steel tank whose volume is 42.0 L and which contains oxygen gas at a pressure of 18,000 kPa at 23° C. What mass of oxygen does the tank contain?

(760 torr = 1 atm = 101,325 Pa, O = 16.00 g/mol, R = 0.08206 L*atm/mol*K, K = 273.15 +°C)

Can someone please help me solve this. The answer is 9,800 g O2, but I keep getting 9.8 X 10^-5 O2.q

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