(Answered) Consider the following reaction between aqueous mercury

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Consider the following reaction between aqueous mercury ions and a complexing agent "RWW" also known as a chelating agent.

Hg^2+ (aq) + 2RWW (aq) <-> Hg(RWW)2^2+ (aq) Kf=7.91E10

Suppose a typical human (about 48 L of water by volume) ingests 510mg of mercuric ions. Consider then a subsequent chelating treatment consisting of injection of 25.0mL of .35M RWW solution. Set up a reaction table (in mmol) for the complexation and calculate the concentration and mass in the body of the uncomplexed mercury. Neglect the volume of RWW solution compared to total body volume.

Hg^2+=______ mass Hg^2+_______mg (answers are 1.15E-7 and 1.104 mg respectively) I want to know how to obtain

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