Consider the dissolving of lead iodide: PbI2 (s) ?? Pb2+ (aq) + 2 I- (aq)
The solubility of lead iodide (like many salts) increases at higher temperatures:
At 20°C, the molar solubility is 1.45 × 10-3M
At 80°C, the molar solubility is 6.85 × 10-3M
From this information, calculate ?H° and ?S° for the above reaction. You may assume that ?H° and
?S° remain constant over this temperature range.