Consider a 150 lb skydiver who steps out of an airplane 2 miles up.

- Gravity accelerates the diver's fall but is decelerated by drag on the chute

- Remember that mass in English units is the slug and g=32.2 ft/s

The governing 1^st order differential equation modelling this scenario is mdv/dt = -mg + kv²

Since the skydiver is simply stepping out of the plane, assume they do so with 0 starting velocity.

The air resistance K(t) is proportional to the square of the velocity and is normally a function of time. However, for the sake of simplicity assume K=4/15.

1. Find the numerical solution using two MATLAB ode solvers, ode45 and ode23. )). Use an anonymous function as the input function for your ode solvers.

2. On the same graph (can do a subplot), plot velocity versus time for each ode solver, and label the plot appropriately.

3. What is the terminal velocity in ft/s according to each solver?

4. What is the terminal velocity in mph?

5. At what time do we reach terminal velocity? Output in seconds

6. Descriptive comments throughout your code.