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Compute the pH for each of the subsequent cases in the titration of 50.0mL of 0.110 M HClO(aq) with 0.110 M KOH(aq). The ionization constant for HClO IS 4.0×10-8

(a) Before addition of any KOH (b) after addition of 25.0mL of KOH (c) after addition of 40.0mL of KOH (d) after addition of 50.0mL of KOH (e) after addition of 60.0mL of KOH = 12.16

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