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Compute the given problem:

Problem: As is known that the wavelength of yellow light from mercury is 578nm. Assuming the yellow light is incident on a photocathode with a work function of 1.46 eV,

Part I: What is the energy of photoelectron when it leave the surface of photocathode?

Part II: What will the measured stopping potential V0? Recall that the stopping potential is the voltage that needs to be applied to stop the flow of all photoelectrons from the cathode.

Part III: For the photocathode, what is the maximum wavelength to excite photoelectrons?

Please show all work so I can fully understand all concepts!

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