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Compute all parts of given question:

Question: A metal rod of length 76 cm and mass 1.79 kg has a uniform cross-sectional area of 7.7 cm². Due to a non uniform density, the center of mass of the rod is 22.2 cm from the right end of the rod. The rod is suspended in a horizontal position in water by ropes attached to both ends.

Part A: What is the tension in the rope closer to the center of mass?

Part B: What is the tension in the rope farther from the center of mass? (Hint: The buoyancy force on the rod effectively acts at the rod's center.)

Please explain how you came to your conclusion.

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