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Calculate the work done (in Joules) when 33.3g of tin dissol
Calculate the work done (in Joules) when 33.3g of tin dissolves in excess acid at 1.04 atm and 22 degrees C. Assume ideal gas behavior.

Sn(s) + 2H(aq) yields Sn2+(aq) + h2(g)

I realize the equations PV=nRT and w=-p (change V) but have converted and can't seem to get it right?

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