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Calculate the value of the equilibrium constant for the reaction that occurs when solid sodium oxalate is dissolved in water.

Ka for oxalic acid =

3.78 x 10-6

H2 C2 O4 ------2H+ + C2O4-2

Original oxalate ion concentration was 5.68 x 10-7

PH of 0.015 M oxalic acid solution is 0.5

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