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Calculate the molar solubility of Ca(IO3)2 in each solution below. The Ksp of calcium iodate is 7.1x10^-7. a.) 0.065 M Ca(NO3)2 b.) 0.065 M NaIO3
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Q1. Sodium metal is very active with water. Therefore, determining the value of a block of sodium will be impossible by water displacement. On the other hand, the density of sodium metal can be found in the chemistry han ...
1. Consider the reaction when aqueous solutions of nickel(II) bromide and sodium carbonate are combined. The net ionic equation for this reaction is: 2. Net ionic equation for the reaction that occurs when aqueous so ...
A chemist must dilute 37.4 mL of 8.08 μM aqueous mercury(I) chloride (Hg2Cl2) solution until the concentration falls to 2.00 μM. He'll do this by adding distilled water to the solution until it reaches a certain final vo ...
With the provided indicated equilibrium constant, Is the equilibrium mixture made up of predominately reactants, predominately products or significant amounts of both products and reactants? 2 O 3 (g) -------- 3 O 2 (g ...
a) Glucose is a carbonate that your body can burn for fuel. It is 40 percent C and 6.71 percent H by mass. The rest is O. What is the empirical formula of glucose b) The molar mass of glucose os 180.0 g/mol. what is the ...
Barium Iodate (Ba(IO3)2) forms an equilibrium with is ions in solution. How does adding additional barium to the solution affect the Ksp of barium iodate. Explain.
How many formula units of Na2SO4are present in a 450 gram sample of the salt? Use 6.022×1023mol-1 or Avogadro's number. Report your answer in scientific notation. Your answer should have two significant figures.
Diagonal relationship and anomalous behaviour of the each element of the periodic table
A mixture containing 3.3 moles of NO and 0.76 mole ofCO 2 was allowed to react in a flask at a certaintemperature according to the equation. NO (g) + CO 2 (g) ↔ NO2 (g) + CO (g) At equilibrium 0.21 mole of CO 2 was pr ...
How many grams of H2SO4 must be dissolved into 0.709 L of solution to generate a concentration of 0.303 M?
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