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Calculate the heat of enthalpy for the reaction:
PCl5(g) → PCl3(g) + Cl2(g)
Use the information below.
P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ
4PCl5(g) → P4(s) +10Cl2(g) ΔH = 3438 kJ
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