Calculate how many whole drops .05 mldrop of 6 m hcl are, Ask an Expert

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You weigh out pure Calcium carbonate.... 0.1740 g a) Calculate how many whole drops (.05 mL/drop) of 6 M HCl are required to dissolve this. (I found this to be 11.59 drops or 12 full drops) How do you do part b? CaCO3 + 2HCl---> Ca2+ +2Cl- +H2O+CO2 please use 4 sig fig in all calculations b) What is the Ca concentration when this is dissolved and diluted to 100.00mL?

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