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Boyle's apprentice observes that the air trapped in air tube occupies 24.8 cm3 at 1.12 atm.by adding mercury to the tube increases the pressure on the trapped air to 2.64atm. assuming constant temperature, determine the new volume of air?
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When .514g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.8 degrees C to 29.4 degrees C. Find delta E(rxn) for the combustion of biphenylin kJ/mol. The heat capacity of the ...
A mixture containing 3.3 moles of NO and 0.76 mole ofCO 2 was allowed to react in a flask at a certaintemperature according to the equation. NO (g) + CO 2 (g) ↔ NO2 (g) + CO (g) At equilibrium 0.21 mole of CO 2 was pr ...
Question - The solubility of O 2 (g) in water is 4.43 mg of O 2 /100g H 2 O at 20 o C and 1 atm pressure. What pressure of O 2 (g) would be required to produce a saturated solution that is 0.010 M O 2 ?
Magnesium metal(0.100 mol) and a volume of aqueous hydrochloric acid that contains0.500 mol of HCl are combined and react to completion. How manyliters of hydrogen gas, measured at STP, are produced? Mg(s) + 2HCl(aq) --- ...
To standardize a solution of NaOH, one uses a primary standard called potassium hydrogen phthalate (KHP for short). It is a monoprotic acid that can be obtained extremely pure and dried to a constant weigh out 0.556g of ...
If you carry out the reaction between table salt (NaCl) and copper(II) sulfate (CuSO4) in 100.0 mL of water, the salt copper(II) sulfate will behave similarly to the salts given in the tab named Slightly Soluble Salts. E ...
Aqueous potassium phosphate was mixed with aqueous magnesium chloride, and a crystallized magnesium phosphate product was formed. Consider the other product and its phase, and then write the balanced molecular equation f ...
The heat fusion of pure silicon is 43.4 kJ/mol. How much energy would be needed to melt a 5.24 - g sample of silicon at its melting point of 1693 K?
What could a source of error be during a titration lab that is not a humans fault?
At rest, a person inhales 9.72*10^21 nitrogen molecules in an average breath of air. How many mole of nitrogen atoms are inhaled? (Hint: in air, nitrogen occurs as a diatomic molecule)
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