Background: If aqueous NaOH is added to tert-butyl chloride acetone solution, initially the solution is basic due to the hydroxide ions from the NaOH. As the t-butyl chloride continues the reaction through hydrolysis and generates HCl, the HCl neutralizes the NaOH ions
Question: If 5.0mL of 0.0091M aqueous NaOH is added to 5mL of 0.091M of tert-butyl chloride in acetone, calculate the pH at 10% hydrolysis. (There is a hint listed that says to calculate moles of HCl produced and compare that number to the moles of NaOH present in the reaction mixture.)