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At what pH would the given concentrations of Ce4+ (1.67*10^-4), Ce3+ (.185), Mn2+ (1.28x10^-5) and MnO4- (.148) be in equilibrium at 298 K. Chemical equation is 5Ce4+ + Mn2+ 4H2O => 5Ce3+ + MnO4- + 8H+. And E standard is .193V

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