At some temperature,a 100-L reaction vessel contains a mixture that is initially 1.00 mol CO and 2.00 mol H2. The vessel also contains a catalyst so that the following equilibrium is attained:

CO(g)+ 2H2(g) <---- ----> CH3OH(g)

At equilibrium, the mixture contains 0.100 mol CH3OH (methanol). In a alter experiment in the same vessel, you start with 1.00 mol CH3OH. How much methanol is there at equilibrium? explain