At 2000 K, Kc = 0.154 for the reaction below.
2 CH4(g) → C2H2(g) + 3 H2(g)
If a 1.75-L equilibrium mixture at 2000 K contains 0.95 mol each of CH4(g) and H2(g), answer the following questions.
(a) What is the mole fraction of C2H2 present? (Note: The mole fraction of C2H2 is equal to the number of moles of C2H2divided by the total number of moles.)
Enter your answer with 2 significant digits.
Enter scientific notation as 1.23E4.
Enter only numbers in your answer. (Do not include units.)
The mole fraction of C2H2 is --------
(b) If the equilibrium mixture at 2000 K is transferred from a 1.75-L flask to 10.0-L flask, will the number of moles of C2H2(g) increase, decrease, or remain unchanged?